Quadratics
Problem Solving
1. A ball was kicked into the air which follows a parabolic path described by the equation:
h=-2(t-4)2+10
Step 1:Make a let statement.
Let h repersent height
Let t repersent time
a)When does the ball reach its maximum height?
-the question is asking how long did it take for the ball to reach its highest point.
-on a paraboa graph the vertex it the higest point
Step 2:Set bracket to 0
h=-2(t-4)2+10
t-4=0
+4+4
t=4
The ball took 4 seconds to reach its highest point.
b)What is the maximum height?
Step 3: Plug in your "t"(x) value into the equation
h=-2(t-4)2+10
h=-2(4-4)2+10
h=-2(0)2+10
h=-2(0)+10
h=0+10
h=10
The maximum height is 10m.
Now You Try!
1. A frisbee was thrown into the air which follows a parabolic path described by the equation:
h=4(t-6)2+2
a)When does the ball reach its maximum height?
b)What is the maximum height?
Answers:a)6 b)2
2.A ball was thrown into the air which follows a parabolic path described by the equation:
h=(t-20)2+3
a)When does the ball reach its maximum height?
b)What is the maximum height?
Answers:a)20 b)3